25. Two chords AB and CD of a circle intersect each other
at P outside the circle. If AB= 6 cm, BP=2 cm and PD
= 2.5 cm, find CD.
Who answer correct , I select him as brainliest...
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1
Answer:
.
Step-by-step explanation:
the answer of this question will be the CD is equal to 5 centimetre .
Answered by
2
Answer:
Your answer is:
The chords intersect each other externally at point P
therefore , by theorem of external division of chords,
AP x BP = CP x DP
AB +BP =6+2=8 =AP
8 x 2=CP x 2.5
CP = 6.4
CP + PD =CD
6.4 + 2.5 =CD
CD=8.9
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