25. Two circles with centres O and P intersect at A and D, as shown in the figure. If AOB and APC are diameters, prove that B, D and Care collinear.
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Join CB, BD and AB, Since, AC is a diameter of the circle with centre O.
∴ ∠ABC = 90° [angle in semi circle] ---- (i)
Also, AD is a diameter of the circle with center O .
∴ ∠ABD = 90° [angle in semi circle] ---- (ii)
on adding Eqns, (i) and (ii) we get
⇒ ∠ABC + ∠ABD = 180°
So. CBD is a straight line.
Hence C, B and D are collinear .
Hence proved.
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