25.
विष्णु को अपना पति कौन मानती थी ?
(A) मीरा
(B)
अंडाल
(C)
कराइकल
(D)
इनमें से सभी
Answers
Answered by
0
Answer:
We have,
ABCD as the cyclic quadrilateral in which the diagonal AC and BD.
intersect each other at point P.
also, given that,
AB=8cm,
CD=5cm
Now,
In ΔDCA and ΔAPB,
We have
∠DCP=∠ABP
∠CDP=∠PAB
Hence,
ΔDPC∼ΔAPB (by A.A property)
According to the given question,
arΔAPBarΔDPC=(ABDC)2
⇒24arΔDPC=(85)2
⇒24arΔDPC=6425
⇒arΔDPV=6425×24
arΔDPC=9.375cm2
Explanation:
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Answered by
0
Answer:andsl
Explanation:
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