Math, asked by bhumeeka31, 7 months ago


25. What are the possible expression for dimension of cuboid whose volume is given by
12ky +8ky-20k
OR
Find the value of K, if (x - K) is factor of x® - kx + x*-kx + 3x - k + 4
26. Express 0.245245.......as a fraction in a simplest form. In form of rational number)

Answers

Answered by Anonymous
6

Answer:

To find the possible dimensions of cuboid whose volume is 12kx

2

+8kx−20k, we factorize 12kx

2

+8kx−20k

=4k(3x

2

+2x−5)

=4k(3x

2

+5x−3x−5)

=4k[3x(x−1)+5(x−1)]

=4k(x−1)(3x+5)

So, the possible dimensions are 4k units, (x−1) units, (3x+5) units

Answered by Anonymous
5

Answer:

25)To find the possible dimensions of cuboid whose volume is 12kx

To find the possible dimensions of cuboid whose volume is 12kx 2

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k=4k(3x

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k=4k(3x 2

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k=4k(3x 2 +2x−5)

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k=4k(3x 2 +2x−5)=4k(3x

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k=4k(3x 2 +2x−5)=4k(3x 2

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k=4k(3x 2 +2x−5)=4k(3x 2 +5x−3x−5)

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k=4k(3x 2 +2x−5)=4k(3x 2 +5x−3x−5)=4k[3x(x−1)+5(x−1)]

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k=4k(3x 2 +2x−5)=4k(3x 2 +5x−3x−5)=4k[3x(x−1)+5(x−1)]=4k(x−1)(3x+5)

To find the possible dimensions of cuboid whose volume is 12kx 2 +8kx−20k, we factorize 12kx 2 +8kx−20k=4k(3x 2 +2x−5)=4k(3x 2 +5x−3x−5)=4k[3x(x−1)+5(x−1)]=4k(x−1)(3x+5)So, the possible dimensions are 4k units, (x−1) units, (3x+5) units

26)see this attachment

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