25. What is the total area of the figure if AB = 12 cm, AC = 24 cm, CE = 6 cm. AD 4.8 cm. CF GE = 3.6 cm, DH = 2.4 cm
a) 50.5 sq.cm
b) 46.8 sq cm
c)648 sq.cm
d) 54.6 sq.cm
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Ur answer is [D] 54.6 Sq.cm
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Answer:
Given : CD is a diameter, AE = BE = 4 cm, CE = 3 cm.
∠OEB = 90° (∵ E is the mid-point of BA).
Let the radius OB = OC = r cm.
Then, OE = OC – CE = (r – 3) cm.
ICSE Class 9 Maths Sample Question Paper 10 with Answers 7
In ΔOBE, by Pythagoras theorem,
OB2 = OE2 + BE2
⇒ r2 = (r – 3)2 + 42
⇒ r2 = r2 – 2.r.3 + 9 + 16
⇒ 6r = 25
⇒ r=256=416
The required radius = 416 cm.
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