Math, asked by psivamabed, 10 months ago

25|x|=x^2+144
answer step by step​

Answers

Answered by tusharbunger
0

Answer:

_/107

Step-by-step explanation:

251-144=x^2

107=x^2

x=_/107

Answered by anushkadas2004
0

Answer:

25|x|=x^2+144

Step-by-step explanation:

25(x2-144)+12(x2-25)=x2  

Two solutions were found :

                  x = ±√ 108.333 = ± 10.40833  

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :  

               25*(x^2-144)+12*(x^2-25)-(x^2)=0  

Step by step solution :

Step  1  :

Trying to factor as a Difference of Squares :  

1.1      Factoring:  x2-25  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =  

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.  

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 25 is the square of 5

Check :  x2  is the square of  x1  

Factorization is :       (x + 5)  •  (x - 5)  

Equation at the end of step  1  :

 ((25•((x2)-144))+12•(x+5)•(x-5))-x2  = 0  

Step  2  :

Trying to factor as a Difference of Squares :  

2.1      Factoring:  x2-144  

Check : 144 is the square of 12

Check :  x2  is the square of  x1  

Factorization is :       (x + 12)  •  (x - 12)  

Equation at the end of step  2  :

 (25•(x+12)•(x-12)+12•(x+5)•(x-5))-x2  = 0  

Step  3  :

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

  36x2 - 3900  =   12 • (3x2 - 325)  

Trying to factor as a Difference of Squares :  

4.2      Factoring:  3x2 - 325  

Check :  3  is not a square !!  

Ruling : Binomial can not be factored as the

difference of two perfect squares

Equation at the end of step  4  :

 12 • (3x2 - 325)  = 0  

Step  5  :

Equations which are never true :  

5.1      Solve :    12   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :  

5.2      Solve  :    3x2-325 = 0  

Add  325  to both sides of the equation :  

                     3x2 = 325  

Divide both sides of the equation by 3:

                    x2 = 325/3 = 108.333  

 

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  

                     x  =  ± √ 325/3  

The equation has two real solutions  

These solutions are  x = ±√ 108.333 = ± 10.40833  

 

Two solutions were found :

                  x = ±√ 108.333 = ± 10.40833  

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