25(x+y)^2-36(x-2y)^2can be factorised as:
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Step-by-step explanation:
25(x+y)^2-36(x-2y)^2
=5^2(x+y)^2-6^2(x-2y)^2
=[5(x+y)]^2-[6(x-2y)]^2
by using the identity a^2-b^2=(a+b)(a-b)
=>[{5(x+y)}-{6(x-2y)}] * [{5(x+y)}+{6(x-2y)}]
=[5x+5y-6x+12y] * [5x+5y+6x-12y]
=[17y-x] * [11x-7y]
this is the final factorised form.
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