25(x+y)^2-9(x-y)^2
pls guys help me
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Answered by
1
25(x+y)^2-9(x-y)^2
= 5^2(x+y)^2 - 3^2(x-y)^2
=[5(x+y)]^2-[3(x-y)]^2
=[5x+5y]^2 - [3x-3y]^2
= [5x+5y+3x-3y][5x+5y-(3x-3y)]
since a^2-b^2= (a+b)(a-b)
=[8x-2y][5x+5y-3x+3y]
=(8x-2y)(2x+8y)
=2(4x-y)*2(x+4y)
=4(4x-y)(x+4y)
= 5^2(x+y)^2 - 3^2(x-y)^2
=[5(x+y)]^2-[3(x-y)]^2
=[5x+5y]^2 - [3x-3y]^2
= [5x+5y+3x-3y][5x+5y-(3x-3y)]
since a^2-b^2= (a+b)(a-b)
=[8x-2y][5x+5y-3x+3y]
=(8x-2y)(2x+8y)
=2(4x-y)*2(x+4y)
=4(4x-y)(x+4y)
mysticd:
in last step 4(4x-y)(x+4y)
Answered by
0
Answer:
25(x+y)^2-9(x-y)^2
= 5^2(x+y)^2 - 3^2(x-y)^2
=[5(x+y)]^2-[3(x-y)]^2
=[5x+5y]^2 - [3x-3y]^2
= [5x+5y+3x-3y][5x+5y-(3x-3y)]
since a^2-b^2= (a+b)(a-b)
=[8x-2y][5x+5y-3x+3y]
=(8x-2y)(2x+8y)
=2(4x-y)*2(x+4y)
=4(4x-y)(x+4y)
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