Question

25) X2+3Y2→ 2XY3 In this reaction 2 moles of X2 and 4.5 moles of Y2 react to give
products. Which is the limiting agent and calculate the no. of moles of X2,
Y2and XY3 in the reaction mixture?​

Answer 1

Answer: 0 moles of $Y_2$

0.5 moles of $X_2$

3 moles of $XY_3$

Explanation:-

The balanced chemical reaction is:

$X_2+3Y_2\rightarrow 2XY_3$

According to stoichiometry:

3 moles of $Y_2$ react with 1 mole of $X_2$

Thus 4.5 moles of $Y_2$ react with =$\frac{1}{3}\times 4.5=1.5moles$ of $X_2$

$Y_2$ is a limiting reagent as it limits the formation of products and $X_2$ is an excess reagent as (2-1.5)=0.5 moles of $X_2$ are left unreacted.

3 moles of $Y_2$ form 2 moles of $XY_3$

Thus 4.5 moles of $Y_2$ react with =$\frac{2}{3}\times 4.5=3moles$ of $XY_3$

Thus there are 0 moles of $Y_2$ , 0.5 moles of $X_2$ and 3 moles of $XY_3$