Question

250
18 years ago, a man was three times as
old as his son. Now, the man is twice as
old as his son. The sum of the present
ages of the man and his son is:​

Answer 1

MAN'S AGE = 72

SON'S AGE = 36

Step-by-step explanation:

LET THE AGE OF HIS SON = x

therefore. the age of man will be 3x

18 years ago,

SON'S AGE = 3x -18

hence, man's age = 2(3x-18)

A.T.Q.

3x - 18 = 6x -36

......

sorry i m confused with the last part...

HOPE THE REST OF THE PARTS HELPS U....

THANKS