250(a-b)^3+2 factorise
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Answered by
261
The answer is given below :
Now,
250(a - b)³ + 2
= 2[ 125(a - b)³ + 1 ]
= 2 [ 5³(a - b)³ + 1 ]
= 2 [ (5a - 5b)³ + 1³ ]
= 2 (5a - 5b + 1) { (5a - 5b)² - (5a - 5b)×1 + 1² }
= 2 (5a - 5b + 1) (25a² - 50ab + 25b² - 5a + 5b + 1),
which is the required factorization.
Thank you for your question.
Now,
250(a - b)³ + 2
= 2[ 125(a - b)³ + 1 ]
= 2 [ 5³(a - b)³ + 1 ]
= 2 [ (5a - 5b)³ + 1³ ]
= 2 (5a - 5b + 1) { (5a - 5b)² - (5a - 5b)×1 + 1² }
= 2 (5a - 5b + 1) (25a² - 50ab + 25b² - 5a + 5b + 1),
which is the required factorization.
Thank you for your question.
Answered by
66
see the attachment ...
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