Question

250 cm
cm3 of
of a solution of oxalie
acid contain 1.26g of oxalic
acid, calculatie its molarity​

Answer 1

Answer:

The molecular formula of oxalic acid is  C2H2O4  and its corresponding molecular mass is  90 .

But, the oxalic acid in powder form that is generally available is a dihydrate of the acid, i.e.  C2H2O4⋅2H2O , of which the molecular as is  126 .

Explanation:

Oxalic acid is a dibasic acid. So, its one mole is 2 equivalents.

So, the normality is:

2×1.26126.250  

=2100×4  

=0.08 N

There you go!