Question

250 J of heat is produced each second in 12 ohm resistance. find the potential difference across the resistor.
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Answer 1

Answer:

The produced heat is given as,

H = I^2Rt

250 = I^2×12×1

250 = 12×I^2

I^2 = 250/12

= √20.8333

= 4.564

The potential difference is given as,

V = IR

= 4.564×12

= 54.768V

Answer 2

Given :

• Heat produced = 250 J
• Time = 1 second
• Resistance across the resistor = 12 ohm

To find :

• Potential difference across the resistor (V)

Solution :

★ We know that heating effect of electric current,

• H=I²RT

★ The above relation of the heating effect can also be written as,

• I² = H/RT

★ Substituting the values:-

→ I² = 250/(12 × 1)

→ I² = 250/12

→ I² = 20.8333

→ I = √20.8333

→ I = 4.564

★ According to Ohm's Law

• V = IR

★ Substituting the values:-

→ V = 4.564 × 12

→ V = 54.768

•°• the potential difference = 54.768 V