250 mL 0.1 M HCl solution is mixed with 250 mL 0.2 M NaOH. The concentration of OH– in the mixture is
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Explanation:
V1M1 - V2M2 = V3 M3
50 ×0.2 - 50× 0.1 = 100 × M3
10 - 5 = 100 M3
M3 = 5/100
M3 = 0.05 M
pOH = -log [OH]
pOH = -log 0.05
pOH = 1.3010
pH + pOH = 14
pH = 14 - pOH
pH = 14- 1.3010
pH = 12.699
when two solutions are mixed (acid and base) both volume and molarity is multipied ,the value which is lowered is subtract from the higher In the above case base value is greater .Therefore the final result is pOH
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