250 ml of a sodium carbonate solution contains 2.65 g Na2CO3.If 10 ml of this solution is diluted to 1 L; Calculate the molarity of the resultant solution.
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M of Na2CO3 = 2.65*1000/53*250
M = 0.2
M₁*V₁= M₂V₂
0.2*250 = M₂*1000
M₂ = 0.05
M = 0.2
M₁*V₁= M₂V₂
0.2*250 = M₂*1000
M₂ = 0.05
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