Question

250 The formation of the centers of the X, Y, and Z atomic species is as follows. Х Y Z Protons 3 6 7 Neutrons 4 6 7 Calculate (i) Atomic number(ii) mass number. Of X, Y, and Z.​

Answer 1

Answer:

Atomic No. : X = 3, Y = 6, Z = 7

Mass No. : X = 7, Y = 12, Z = 14

Explanation:

Atomic No. is equal to the number of protons,

So atomic no. of X = 3, of Y = 6 and of Z = 7

Mass No. is equal to the sum of no. of protons and no. of neutrons,

So mass no. of X = 3+4 = 7, of Y = 6+6 = 12 and of Z = 7+7 = 14