Question

2500 cc of oxygen was burnt with 600 cc of ethane.calculate the volume of unused oxygen and thye volume og carbon dioxide formed

Answer 1

Hello friend!!
Rajdeep here...

Reaction is:
2C2H6 + 7O2 ------> 4CO2 + 6H2O
Hence, volume ratio is 2:7:4

2 volumes of Ethane = 600cc
Hence, 1 volume of ethane = 600/2 = 300cc

7 volumes of oxygen = 2500cc
Hence, 1 volume of oxygen = 2500/7 = 357.14cc

One volume of ethane is less than that of oxygen, this means that ethane is fully used in the reaction and oxygen is unused, so we will take the one volume of C2H6, I.e., 300cc for calculation.

So volume of oxygen used in the reaction is
7 x 300cc = 2100cc.
So unused O2 is 2500 - 2100 = 400cc

Also, volume of CO2 formed = 4 x 300cc = 1200cc.

Hope you understand this process..
This is an uncommon but easy process...

Thanks!!