Question

250cm^3 of a solution of oxalic acid contain 1.26g of oxalic acid. Calculate it's molarity

Answer 1

Equivalent weight of oxalic acid is 63 gram

We are using 1.26 gram

Volume of the solution is 250 ml

Now,

Normality of oxalic acid=

(weight of acid×1000)/(eq. Weight×vol.of sol.)

= (1.26×1000)/(63×250)

=0.08 N