250g water and equal volume of alcohol of mass 200g are replaced successively in the same calorimeter and cool from 60oC to 55oC in 130s & 67s respectively.if the water equilvalent of the calorimeter is 10g,then the specific heat of alcohol
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Hello dear,
● Answer- 1.21 cal/g/°C
● Explanation-
# Given-
Specific heat of water = 1 cal/g/°C
Density of alcohol = 1×200/250 = 0.8 g/cm^3
# Solution-
Specific heat of alcohol
x = 1 × (60-55) × (130/67) / (0.8 × 10)
x = 1.21 g/cal/°C
Therefore specific heat of alcohol is 1.21 g/cal/°C.
Hope this is useful...
● Answer- 1.21 cal/g/°C
● Explanation-
# Given-
Specific heat of water = 1 cal/g/°C
Density of alcohol = 1×200/250 = 0.8 g/cm^3
# Solution-
Specific heat of alcohol
x = 1 × (60-55) × (130/67) / (0.8 × 10)
x = 1.21 g/cal/°C
Therefore specific heat of alcohol is 1.21 g/cal/°C.
Hope this is useful...
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