Question

250ml (6m hno₃) and 350ml (8m hno₃) are mixed to make the strength of the resulting solution 3n, what is the volume of water required to be added -

Answer 1

Answer:

Step1: Apply the molarity formula to calculate the moles of HNO3.

HNO3 moles = 2M x .250 L = 0.50 moles.

Step2: Convert the moles of HNO3 into mass.

Mass = moles x molar mass = 0.50 moles x 63.01g/mole = 31.5 g HNO3.

Thus, 31.5 g HNO3 will be present in 100g x 31.5 g HNO3/70g = 45g solution.

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