250ml of 0.1N solution of hcl contains
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Normality=No. of equivalent/Volume in L
No. of equivalents=0.1×1/4=.025
Since the basicity of HCL is 1
No. of equivalents=No of moles=0.025
No. of equivalents=0.1×1/4=.025
Since the basicity of HCL is 1
No. of equivalents=No of moles=0.025
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