250ml of oxygen takes 100 sec.to effuse .what volume of carbon dioxide gas will effuse under similar conditions in 150 sec? (molecular weight of carbon dioxide= 44 g mol-1)
Answers
Answer:
319.8 ml
Explanation:
This is a question on gas laws Graham's law of diffusion
There are different volumes of gases hence the formula to be used is
Rate of oxygen/rate of carbon dioxide = √Molecular mass of carbon dioxide/molecular mass of oxygen
To get the rates we take the volume divide by the time given
Oxygen rate = 250 ml ÷ 100 seconds = 2.5 ml per second
We cannot get the rate of carbon dioxide because we do not have the volume so we denote it as x
The mm of oxygen is 16 × 2 = 32
That of carbon dioxide is 44
We can therefore apply the formula
2,5/x = √44/32
2.5/x = 1.1726
X = 2.132ml/sec that is the rate of carbon dioxide
To get the volume we multiply the time by the rate
150 × 2.132 = 319.8 ml
Answer:
V1 = 250ml V2 =?
T1= 100 SEC T2=150 SEC
MOL.WT OF O2= 32 MOL.WT OF CO2 =44
r1/r2 =v1/t1 ×t2/v2 = m2/m1
250/100 ×150/v2 =44/32 (root under)
375/v2 =44/32 ( rootunder)
375/v2 =6.63/5.65
v2 =211875/663
v2 =319.5 ml