250ml round bottom flask was heated from 25 to 75 degree find friction of air left behind
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Secondary SchoolChemistry 5 points
250 ml round bottom flask containing air was heated from 27°C to 477°C.Calculate what fraction of air is left behind in the flask?
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Answer: 38.45% of gas will be left behind in the flask.
Explanation:
Given:
V_1=250 mL=0.25L (1L=1000mL)
V_2=?
T_1=27^oC=273.15+27 K=300.15 K (0^oc=273.15 K)
T_2=477^oC= 750.15 K
According to Charle's law:
\frac{V_1}{T_1}=\fracx{V_2}{T_2}
\frac{0.25L}{300.15K}=\frac{V_2}{750.15K}
V_2= 0.65L
As, seen from the Volume, we can say that gas is being expelled out of the flask.
\text{Fraction of gas left behind in the flask}=\frac{0.25}{0.65}\times 100=38.46\%
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