251÷8×p^2 what is the value of p
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Correct option is
D
None of these
Given the points of triangle, A(p,2−2p),B(1−p,2p) and C(−4−p,6−2p)
Area =70sq.unit
=
2
1
[x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)x
3
(y
1
−y
2
)]=70
{p[2p−6+2p]+(1−p)[6−2p+2p]+(−4−p)[2−2p−2p]}=140
p(4p−6)+(1−p)(4)−[(4+p)(2−4p)]=140
4p
2
−6p+4−4p−[8−16p+2p−4p
2
]=140
4p
2
−6p+4−4p−8+16p−2p+4p
2
=140
8p
2
+4p−144=0
2p
2
+p−36=0
2p
2
+9p−8p−36=0
p(2p+9)−4(2p+9)=0
(2p+9)=0,(p−4)=0
p=−9/2,p=4
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