Question

251
Mensuration
The diameter of a circular park is 84 m. A 3.5 m wide road runs on the outside
around it. Find the cost of constructing the road at 200 per m.
84
Radius of the circular park = m = 42 m.
Width of the road = 3.5 m.
Radius of the outer circle = (42 + 3.5) m = 45.5 m.
Area of the road
= (area of outer circle) - (area of inner circle)​

Answer 1

Answer:

rupees 192500

Step-by-step explanation:

area of road = (22/7)[(45.5x45.5) - (42x42)] = (22/7)(2070.25 - 1764)

= 962.5sq.m

cost of constructing = 962.5 x 200 = rupees 192500