Question

252, 294 और 3 #8 का म.स. (HCF) 42 है।तो # क्या है

Answer 1

SOLUTION

GIVEN

The HCF of 252 , 294 , 3#8 is 42

TO DETERMINE

The value of #

EVALUATION

Here it is given that the HCF of 252 , 294 , 3#8 is 42

Clearly

42 × 6 = 252

42 × 7 = 294

Now we have to find the three digit number multiple of 42 and starts with 3 & ends with 8

Now

42 × 8 = 336

42 × 9 = 378

42 × 10 = 420

Thus we see that 378 is the only three digit number multiple of 42 and starts with 3 & ends with 8

Thus 3#8 = 378

Thus the number is place of # is 7

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If HCF of two numbers be 40 then which of the following cannot be their LCM.

https://brainly.in/question/28609013

2. The HCF and LCM of two numbers are 17 & 1666 respectively. if one of the numbers is 119 find the other

https://brainly.in/question/13812250