Question

252 Joules of heat are added to 20.0 kg of Mercury to reach a final temperature of 130 Celsius. What was the initial temperature of the Mercury? [Cp of Hg= 0.14 J/g(C)]

Answer 1

Nov 2016 · 4790J=222g⋅4.19⋅(x °C−27.7°C). Note that I let x represent the final temperature. And now, all you ...

Answer 2

hey mates your answer is here

..

Answer:

This will require

266.9

k

J

of heat energy.

Explanation:

To calculate the energy required to raise the temperature of any given substance, here's what you require:

The mass of the material,

m

The temperature change that occurs,

Δ

T

The specific heat capacity of the material,

c

(which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.

Here is a source of values of

c

for different substances:

http://www2.ucdsb.on.ca/tiss/stretton/Database/Specific_Heat_Capacity_Table.html

Once you have all that, this is the equation:

Q

=

m

×

c

×

Δ

T

(

Q

is usually used to symbolize that heat required in a case like this.)

For water, the value of

c

is

4.186

J

g

°

C

So,

Q

=

750

×

4.186

×

85

=

266

858

J

=

266.858

k

J

may be it's helpful for you

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