Question

25200J of heat are added to 2.0 kg of mercury to reach a final temperature of 130 C. if you know that sp. heat of mercury is 183 j/Kg.oC

What was the initial temperature of the mercury?

Answer 1

Hey user !!

Here's the answer you are looking for

We know,

∆Q = m•s•∆T

Where, ∆Q is the heat/energy supplied, ∆T is the change in temp. , m is the mass and S is the specific heat.

A/c to the question,

∆Q = 25200J

m = 2kg

s = 183 J/kg°C

So,
25200 = 2 × 183 × ∆T

∆T = 25200/(183 ×2) = 68.85

So, Tf - Ti = 68.85

Question says Tf ( final temp.) is 13°C

So, Ti = (13 - 68.85)°C = -55.86°C

☛ Initial temp = (-55.86 + 273)K = 217.14K (ans)