Question

256,442and 940 HCF
For divison​

Answer 1

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Formula Used:-

Euclid's Division Lemma ⇒ a = bq + r where 0 ≥ r > b

H.C.F of 256 and 442

442 ⇒ 256 × 1 + 186

256 ⇒ 186 × 1 + 70

186 ⇒ 70 × 2 + 46

70 ⇒ 46 × 1 + 24

46 ⇒ 24 × 1 + 22

24 ⇒ 22 × 1 + 2

22 ⇒ 2 × 11 + 0

∴ H.C.F of 256 and 442 is 2

Now, H.C.F of 2 and 940

940 ⇒ 2 × 470 + 0

∴ H.C.F of 256, 442 and 940 is 2

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Answer 2

To Find: the HCF of 3 Numbers 256,442 and 940

Find the product of its prime factors of 256:

256=2×2×2×2×2×2×2×2

256=2⁸

Find the product of its prime factors of 442:

442=2×13×17

Find the product of its prime factors of 940:

940=2×2×5×47

940=2²×5×47

Find the HCF of the 3 numbers:

256=2⁸

442=2×13×17

940=2²×5×47

HCF is the common factor among the three numbers

=HCF=2

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