Question

(256/6561)^3/8- evaluate the sum​

Answer 1

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(256/6561)^3/8

= (16/81)^2 × 3/8 [2 & 8 are cancelled in the powers, hence 3/4 is left]

=(4/9)^2 × 3/4 [2 & 4 are cancelled in the powers, hence 3/2 is left]

=(2/3)^ 2 × 3/2 [ 2 & 2 gets cancelled in the powers n 3 is left]

Alas, we are left with (2/3)^3

(2/3) × (2/3) × (2/3) = 0.296296..

Answer 2

Answer:

step by step explanation