Math, asked by badarinath7777, 8 months ago

(256) to the power 1/2 + (64) to the power 1/6 + (125) to the power 1/3 ​

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Answered by pulakmath007
6

\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p>

 {256}^{ \frac{1}{2} }  +  {64}^{ \frac{1}{6} }  +  {125}^{ \frac{1}{3} }

 =  { ({16}^{2} )}^{ \frac{1}{2} }  +  { ({2}^{6}) }^{  \frac{1}{6} }  +  {( {5}^{3} )}^{ \frac{1}{3} }

 = 16 + 2 + 5 = 23

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Answered by tennetiraj86
1

Answer:

answer for the given problem is given

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