Math, asked by saanvisamal2799, 6 months ago

(256)^-(x-3/2)=2^-20,find x​

Answers

Answered by shubhangiii
1

Answer:

x = 1

Step-by-step explanation:

(256)^-(x-3/2)=2^-20

=> (2^8)^-(x-3/2) = 2^-20

=> (2)^- 8*(x-3/2) = 2^-20

As base is same we can equate the powers

- 8*( x-3/2 ) = -20

=> x-3/2 = 20 / 8

=> x = 5 / 2 + 3 / 2

=> x = 5 /5

=> x = 1

Answered by vinaymadivalcoc
0

Answer:

x=4

Step-by-step explanation:

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