Math, asked by riya375, 1 year ago

(256a^16÷81b^4)^-3/4

Answers

Answered by YASH3100
78
(256a^16/81b^4)^-3/4
=> (81b^4/256a^16)^3/4
=> (3b/4a^4)^3 [(81b^4)^1/4 = 3b and (256a^16)^1/4 = 4a^4)]
=> 27b^3/64a^12 (ans)


Hope it helps you buddy.
Thank you.
Answered by aswani1963
40

Answer: (27b^3/64a^12)

Step-by-step explanation:

(256a^16/81b^4)^(-3/4)

To remove minus sign reciprocal the equation: (81b^4/256a^16)^3/4

Reduce it to its lowest term: (3b/4a^4)^3

Multiply the given equation by 3 : (27b^3/64a^12) (Ans)

Hope it helps you

Thank you

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