Math, asked by muskan9158, 10 months ago

) 256x2 - 32x + 1 = 0​

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Answered by Anonymous
2

Answer:

256x {}^{2}  - 32x + 1 = 0 \\  \\ 256x {}^{2}  - 16x - 16x + 1 = 0 \\ \\  16x(x - 1) - 1(16x - 1) = 0 \\   \\ (x - 1)(16x - 1) = 0 \\  \\ x = 1 \\ x =  \frac{1}{16}

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