Question

259.The current through the current coil of a wattmeter is given by
i = (1 + 2sin wt) A and the voltage across the pressure coil is
V= (2 + 3 sin 20t) V. The wattmeter will read
(a) 8.00 W (b) 5.05 W (c) 2.0 W (d) 1.0 W

Answer 1

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