Math, asked by vsnuniarampura477, 9 months ago

25a²-4b²+28bc-49c²=25a²-[4b²-28bc+49c²]

Answers

Answered by IbadurRahmanLaskar
11

Step-by-step explanation:

=25a²-4b+28bc-49c²

=25a²-4b+28bc-49c²

=(5a)²-(2b)²+2×2b×7c-(7c)²

=5a²-{2b-7c}² [a²+2ab-b²=(a+b)²

=(5a²+2b-7c) (5a²-2b-7c) [a²-b²=(a+b)]

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