Question

25a²-4b²+28bc-49c²
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Answer 1

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Answer 2

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Step-by-step explanation:

25a2−4b2−28bc−49c2

=(5a)2−(2b)2+28bc−(7c)2

=(5a)2−{(2b)2+2×2b×7c−(7c)2}

      ∵[(a+b)2=a2+b2+2ab]

=(5a)2−(2b+7c)2

       ∵[a2−b2=(a−b)(a+b)]

={(5a)−(2b+7c)}{(5a)+(2b+7c)}

=(5a−2b−7c)(5a+2b+7c)