25a²-4b²+28bc-49c² factorise
Answers
Answered by
9
Answer:
(5a-2b-7c) (5a+2b+7c)
Step-by-step explanation:
5a²)-(2b)²-28bc-(7c)²
(5a²)-{(2b)²+28bc+(7c)²}
(5a²)-{(2b)²+2×2b×7c+(7c)²}
(5a²)-(2b+7c)² [(x+y)²=x²+2xy+y²]
{(5a²)-(2b+7c)²} {(5a²)+(2b+7c)²} [x²-y²=(x-y) (x+y)
= (5a-2b-7c) (5a+2b+7c)
Mark me Brainliest!!
siddharthkalyan:
wrong
Answered by
3
Step-by-step explanation:
25a² - 4b² + 28bc - 49c²
5²a² - 2²b² + 28bc - 7²c²
(5a)² - (2b)² + 28bc - (7c)²
this is not the answer
Similar questions