Math, asked by sainipro18, 21 hours ago

25a²+9b²+c²-30ab+6bc-10ac​

Answers

Answered by vikkiain
0

(5a - 3b -c )^{2}

Step-by-step explanation:

Given, \:  \:  25a²+9b²+c²-30ab+6bc-10ac \\ (5a)^{2}  + ( - 3b)^{2}  + ( - c)^{2}  +  2 (5a \times  - 3b) + 2(  - 3b \times -  c ) + 2 (5a \times  - c) \\ we \:  \: know \:  \:  \boxed{(x + y + z)^{2}  =  {x}^{2}  +  {y}^{2}  +  {z}^{2}  + 2xy + 2yz + 2xz} \\ so, \:  \:  \:   \:  =  >   \:  \:  \: (5a - 3b -c )^{2}

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