Math, asked by masdamahamod, 1 year ago

25e²-16 factoring polynomials


alokpal47788: (5e-4)(5e+4)

Answers

Answered by surendarrajawat
5
Hey
This must be your answer.
Hope it helps :)
Attachments:

masdamahamod: thank you very much <3
alokpal47788: hey factor is not solve
alokpal47788: only factor
alokpal47788: ya
alokpal47788: good
Answered by smithasijotsl
2

Answer:

The factorization of 25e²-16 =  (5e+4)(5e-4)

Step-by-step explanation:

The given expression is 25e²-16

To find,

factorize 25e²-16

Solution:

Recall the identity

a² - b² = (a+b)(a-b)

25e²-16 = (5e)² - 4²

Applying the identity a² - b² = (a+b)(a-b), we get

(5e)² - 4² = (5e+4)(5e-4)

25e²-16 =  (5e+4)(5e-4)

∴ The factorization of 25e²-16 =  (5e+4)(5e-4)

#SPJ3

Similar questions