Question

25g ethyl alcohol ,25g acetic acid and 50g of benzene . calculate the mole fraction

Answer 1

Answer:

Molar mass of ethyl alcohol = 46

Molar mass of acetic acid = 60

Molar mass of benzene = 78

Now N.o of moles = given mass/molar mass

N.o of moles of ethyl alcohol = 25/46 = 0.54

N.o of moles of acetic acid = 25/60 = 0.41

N.o of moles of benzene = 50/50= 1

total n.o of moles of mixture = 0.54+0.41+1 = 1.95

Mole Fraction =

N.o of moles of given compound / total n.o of moles of mixture

mole fraction  of ethyl alcohol = 0.54/1.95 = 0.27

mole fraction of acetic acid = 0.41/1.95 = 0.2

mole fraction of benzene = 1/1.95= 0.51

Hope it Helps!