Question

25kg of N2 and 5 kg of H2 are mixed to produce ammonia (NH3). Calculate the ammonia formed.

Answer 1

Answer:

1666.66 moles of Ammonia is formed

Explanation:

N2 + 3H2 -----> 2NH3

moles of N2 present = 25×10³ ÷ 28 = 892.85moles

moles of H2 present = 5000÷ 2 = 2500 moles

{case -I}

for 1mole N2, 3 mole of H2 is required

therefore for , 892.85 moles of N2, (892.85×3 = 2687.55moles of H2 is required

{CASE- II}

FOR 3 moles H2 , 1mole N2 is required

for 1 mole of H2 , (1/3) moles of N2 is required

for 2500 moles of H2 , (2500/3 = 833.33 moles of N2 is required

therefore

833.33moles of N2 react with 2500 moles of H2

to produce NH3

now 1mole N2 produce 2mole NH3

therefore, 833.33 moles of N2 produce, (833.33×2 = 1666.66 moles of NH3

Answer 2

Answer:

2.839 kg Ammonia is formed.