Question

25kg of N2 and 5 kg of H2 are mixed to produce ammonia (NH3). Calculate the ammonia formed.

Answer 1

Answer: 653.43 mol of NH3

Explanation: Equation N2+3H2  -> 2NH3

1 Kg of N2 = 1000gm N2

25 Kg of N2 = 25 x 1000 = 25000/28 = 892.85 mol

1 Kg of H2 = 1000 gm H2

5 Kg of H2 = 5x 1000 = 5000/2.016 = 2480.15 mol

According to above equation 1 mol of N2(g) requires 3 moles of H2(g)

Hence 892.85 mole of N2 and the mols of H2 required would be

892.85 x 3 mol of H2 / 1 mol N2

= 2678.55 mol = 2.67855 x 103 mol H2

But we have 2480.15 mol of H2. Hence in this process 2678.55 mol of H2 is required.

3 moles of H2(g) ->  2 moles of NH3

2480.15 mole of H2 ->  1653.43 mole of NH3 gas is formed

( 2480.15 / 3 )x 2 = 1653.43 mol of NH3