Question

25m +22n = -19 ;22m+25n = -28​

Answer 1

Answer:

answer is given above hope this answer will help you

Answer 2

Answer:

m = 1

n = -2

Solution:

Given equations are :

25m +22n = -19 -------(1)

22m + 25n = -28 -------(2)

Adding eq-(1) and (2) , we get ;

=> 25m + 22n + 22m + 25n = -19 + (-28)

=> (25m + 22m) + (22n + 25n) = -19 - 28

=> 47m + 47n = -47

=> 47(m + n) = -47

=> m + n = -47/47

=> m + n = -1 -------(3)

Now,

Consider eq-(1)

=> 25m +22n = -19

=> (3m + 22m) + 22n = -19

(25m = 3m + 22m)

=> 3m + 22m + 22n = -19

=> 3m + 22(m + n) = -19

=> 3m + 22×(-1) = -19

{using eq-(3) , m + n = -1}

=> 3m - 22 = -19

=> 3m = 22 - 19

=> 3m = 3

=> m = 3/3

=> m = 1

Now,

Putting m = 1 in eq-(3) , we have ;

=> m + n = -1

=> 1 + n = -1

=> n = -1-1

=> n = -2

Hence,

The required values of m and n are 1 and (-2) respectively.