25ml of a soln of Na2Co3 having a specific gravity of 1.25 required 32.9ml of a soln of HCL containing 109.5gm of the acid per litre for complete neutralization. Calculate the volume of 0.84N H2So4 that will be completely neutralized by 125gm of the Na2Co3 soln.
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25ml of a solution of na2c03 having a sepcific gravity of 1.25g solution of hcl containing 109.5g of the acid per litre for complete neutralization. Calculate the volume of 0.84N h2s04 that will be compltetly neutralized by 125g of na2c03 solution.
In first part I understand
109.5g/36.5g/mol = 3M
And then 3M x 0.0329L = 0.0987/2 0.04935
In second I do not still understand
How do get 470ml
Step by step explain
Explanation:
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