Question

25p^2-80pq+64q^2
Factorise the given term

Answer 1

Answer:

25p^2-80pq+64q^2

=(5p)^2-2×p×q+(8q)^2

=(5p-8q)^2

Answer 2

Step-by-step explanation:

25p^2-80pq+64q^2

= $(5p)^{2} - 2 * 5p * 8q + (8q)^{2}$                   [∵ a$a^{2} - 2ab +b^{2} = (a-b)^{2}$]

= $(5p-8q)^{2}$ (Ans)