Question

25pq/5p^2 ×25pr/12q​

Answer 1

Answer:

$\frac{25pq}{5 {p}^{2} } \times \frac{25pr}{12q} \\ \\ = \frac{5p(5q)}{5 {p}^{2} } \times \frac{25pr}{12q} \\ \\ = \frac{5q}{p} \times \frac{25pr}{12q} \\ \\ = \frac{125pqr }{12pq} \\ \\ = \frac{pq(125r)}{12pq} \\ \\ = \frac{125r}{12}$

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Answer 2

Answer:

257pq+678pq+5767/6878

hope you get it no explanation