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Answers
(i) We may observe that point (0, 32) and (-40, -40) satisfy the given equation. So these points are solutions of this equation.
Now we can draw the graph of above equation as below (ii) Temperature = 30oC So temperature is Fahrenheit is 86o F. (iii) Temperature = 95o F So temperature in Celsius is 35oC. (iv) So, if C = 0oC, F = 32o F
If F = 0o So if F = 0oF, C = - 17.8oC (v) Yes there is a temperature - 40o which is numerically same in both Fahrenheit and Celsius.
PLS MAKE BRAINLEAST AND FOLLOW
Answer:
(i) We may observe that point (0, 32) and (-40, -40) satisfy the given equation. So these points are solutions of this equation.
Now we can draw the graph of above equation as below (ii) Temperature = 30oC So temperature is Fahrenheit is 86o F. (iii) Temperature = 95o F So temperature in Celsius is 35oC. (iv) So, if C = 0oC, F = 32o F
If F = 0o So if F = 0oF, C = - 17.8oC (v) Yes there is a temperature - 40o which is numerically same in both Fahrenheit and Celsius.
PLS MAKE BRAINLEAST AND FOLLOW
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