Question

-25sin^2 thita- 32sin thita- 7=o .find the value of sin thita.​

Answer 1

-25sin^2@ - 32sin@ - 7= 0

=> 25sin^2@ + 32sin@ + 7= 0

=> 25sin^2@ + 25sin@ + 7sin@ + 7= 0

=> 25sin@ (sin@ + 1) + 7 (sin@ + 1) = 0

=> (sin@ + 1) (25sin@ + 7) =0

=> (sin@ + 1) = 0. or,. (25sin@ + 7) =0

now,

(sin@ + 1) = 0

=> sin@ = -1

or,

(25sin@ + 7) =0

=> sin@ = -(7/25)

so, the value of sin thita = (-1) or, (-7/25)