Question

25th term of an AP is three times its 11th term then 4th term of an AP is

Answer 1

Answer:

0

Step-by-step explanation:

let 1st term = a and common difference = d

nth term = tn = a+(n-1)×d

4th term = t4 = a+3d

11th term = t11 = a+10d

25th term = t25 = a+24d

given,

25th term = 3×11th term

=> t25 = 3t11

=> a+24d = 3×(a+10d)

=> a+24d = 3a+30d

=> 3a+30d-a-24d = 0

=> 2a+6d = 0

=> 2(a+3d) = 0

=> 2×t4 = 0

=> t4 = 0